Conditional Expectations in Risky Zero-Coupon Bond Pricing
Summary
The document examines pricing a zero-recovery risky zero-coupon bond by taking the expected discounted payoff conditional on survival to maturity. It presents a survival probability expressed through the integrated default intensity, then uses iterated expectation to motivate a pricing expression involving the short rate and intensity together. The central modeling issue is what information is represented by conditioning on the intensity process and whether the discount factor can be moved outside a conditional expectation.
The response describes the intensity process as information about default risk and says separating discounting from survival requires care. In particular, it acknowledges that moving the random discount factor outside an expectation conditional on default time requires an independence assumption; it also notes that independence between rates and default intensity is often used for simplification. The treatment is conceptual and does not establish all filtration or dependence assumptions needed for the displayed pricing identity, so those assumptions must be checked in a specific credit model.
Key ideas
- The bond payoff is discounted and paid only if default has not occurred by maturity.
- The survival probability is represented using the integrated default intensity.
- Iterated expectation can condition on information about the intensity process.
- A random discount factor cannot generally be removed from conditional expectation without suitable measurability or independence assumptions.
- Assuming rates and default intensity are independent simplifies the pricing calculation.
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Full text
# Law of iterated expectation for the pricing of a Zero Recovery Risky Zero Coupon Bond
# Law of iterated expectation for the pricing of a Zero Recovery Risky Zero Coupon Bond
I am currently reading "Modelling single-name and multi-name credit derivatives" by Dom O'Kane but I struggle at one point that should be relatively easy.
Let us consider a Zero Recovery Risky Zero Coupon Bond, that is to say a bond that pays 1 in case there is no default $\tau > T$ (that is the time of default arives after maturity time)
The pricing formula for such a product is thus given by: $Z(0, T) = E\left[\exp\left(-\int_0^T r(t)dt\right) \cdot \mathbb{1}( \tau > T)\right]$.
We also know that: $P(\tau > T) = \exp\left(-\int_0^T \lambda(t)dt\right)$.
In order to simplify the writing of $Z(0, T)$, here are the steps that are presented: $Z(0, T) = E\left[\exp\left(-\int_0^T r(t)dt\right) \cdot \mathbb{1}( \tau > T)\right]$.
Using the law of iterated expectation, we have:
$Z(0, T) = E\left[E\left[\exp\left(-\int_0^T r(t) dt\right) \cdot \mathbb{1}(\tau > T) | {\lambda(t)}_{t \in [0,T]}\right]\right]$.
And as $E\left[I(\tau > T) | \mathcal{\lambda(t)}_{t \in [0,T]}\right] = \text{P}(\tau > T) = \exp\left(-\int_0^T \lambda(t)dt\right)$.
So one has: $Z(0, T) = \mathbb{E}\left[\exp\left(-\int_0^T (r(t) + \lambda(t)) dt\right)\right]$.
Question 1: Why is the filtration selected the set of $\lambda(t)$?
Question 2: How can we split and write this: $E\left[\exp\left(-\int_0^T r(t) \, dt\right) \cdot \mathbf{1}_{\tau > T} \,|\, \tau\right] = \exp\left(-\int_0^T r(t) \, dt\right) \cdot E\left[\mathbf{1}_{\tau > T} \,|\, \tau\right]$ if we did not make any assumption on the independence of $r$ and $\lambda$?
## Answer by TourEiffel (score 3, accepted)
https://quant.stackexchange.com/a/75644
In the context of credit risk and stochastic calculus, the filtration of a stochastic process, denoted by {F_t}, represents the accumulated information up to time t. This concept allows for the consideration of new information as it is revealed over time. Now, let's get into the specifics of your questions.
Question 1: The filtration chosen is the set of λ(t) as λ(t) represents the intensity of the default process τ and therefore contains all information about the default risk up to time t. In the case of modelling credit derivatives, knowing the default intensity is crucial in pricing. The filtration {λ(t)} contains all the available information about this default intensity. This means it contains all the necessary information we have up until time t to decide whether or not a default will occur after time T.
Question 2: Regarding the expectation, there seems to be a misunderstanding here. What you're describing isn't the separation of the integral of r(t) and λ(t), but rather, the application of the law of total expectation (or iterated expectations).
The law of total expectation states that the expected value of a random variable can be calculated by taking the expected value of the conditional expected value of the variable on a smaller sigma algebra. This allows us to separate the probability of default event (τ>T) from the discounting factor. It's not about the independence between r and λ, but the application of the law of total expectation.
In the equation E[exp(−∫T0r(t)dt)⋅1(τ>T)|τ]=exp(−∫T0r(t)dt)⋅E[1(τ>T)|τ], the independence between r and τ is assumed. Therefore, we can treat r as deterministic when considering the expectation given τ. This allows us to move exp(−∫T0r(t)dt) out of the expectation operator, as it doesn't involve τ.
Do note that this sort of simplification can often be found in credit risk modelling as we usually consider the short rate r and the default intensity λ as independent, which simplifies the calculations while still capturing the core features of the credit derivative's behavior.Shown in full with attribution under the source's licence. Licence: CC BY-SA 4.0 (Stack Exchange)
This summary was written by Stratmill's research agent from the original; it is not a copy of the source.