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Delta Hedging American Calls with Continuous Dividend Yield

Article Quant Q&A · Author: qp212223

Summary

The document asks whether a continuous dividend yield changes the hedge ratio for an American call in a one-step binomial model. The questioner reasons that a share’s value including reinvested dividends should alter the stock-price difference used in the delta calculation. The responses explain that the binomial tree specifies up and down movements as a modeling choice, while the dividend yield affects the risk-neutral expected asset price and the valuation at each node. For an American option, node values compare continuation value with immediate exercise; for a European option, they use discounted expected value.

A second response says dividend yield is incorporated when calculating the up and down stock values. Together, these explanations suggest the proposed extra dividend adjustment should not be appended mechanically to the hedge ratio when the tree is consistently defined. The discussion is brief and points to further sources rather than deriving the tree or hedge algebra in full, so implementation details depend on the chosen binomial convention.

Key ideas

  • The hedge ratio depends on the stock and option values defined at the tree’s nodes.
  • A consistent tree incorporates dividends in the expected asset price over each step.
  • American option values compare continuation value with immediate exercise value.
  • Dividend adjustments should not be added twice when constructing the stock-price moves.

Tags

Full text
# Delta hedging for an American call option on a stock with a continuous dividend yield


# Delta hedging for an American call option on a stock with a continuous dividend yield












Let the dividend yield be $\delta$ and $C_u, C_d$ and $S_u, S_d$ be the up and down values for the stock and the call respectively over the period $\Delta t$.

In Hull and all other resources I've looked at, the hedge ratio stays the same in this case as the no dividend yield case, i.e. $$\Delta = \frac{C_u - C_d}{S_u - S_d}$$ which confuses me because the payoff of owning one share of stock is actually $S_u e^{\delta \Delta t}$ or $S_d e^{\delta \Delta t}$ so I would presume that the hedge ratio should shift to be $$\frac{C_u - C_d}{S_u - S_d} \exp (-\delta \Delta t)$$ Why is this not the case?

My attempt at a "reasonable" explanation:

Over short $\Delta t$ we have $\exp(\delta \Delta t) \approx (1+ \delta \Delta t)$ so that the approximate payoffs from the stock are $S_u + S \delta \Delta t$ in the up position and $S_d + S \delta \Delta t$ in the down position, where $S$ is the initial price of the stock, asymptotically, so we may just take the denominator in the hedge ratio to be $$S_u + S \delta \Delta t - (S_d + S \delta \Delta t) = S_u - S_d$$ as usual.

## Answer by Kermittfrog (score 1)

https://quant.stackexchange.com/a/60109

If I may draw your attention the answer I gave on this post here: "risk neutral probability for stock with continuous dividend" There I explain how the binomial tree is set up originally, and there you can see why you simply work with $U=e^{\sqrt{\Delta t}\sigma}$ and $D=U^{-1}$ as a modeller's choice. The influences from the dividend yield (conveniently, continuous in your case) and the payoff type (American) are then captured in the expected price of the asset per time-step (must equal the forward price at that step) and in the value per node (discounted expectation in the European case or discounted expectation vs. immediate execution in the American case).

HTH?

## Answer by Valometrics.com (score -3)

https://quant.stackexchange.com/a/60101

The dividend yield is already included when computing $S_u$ and $S_d$. Please check the formula (10.9) in the link below that gives u and d using risk free rate, dividend yield and volatiltiy:

http://www.princeton.edu/~markus/teaching/Eco467/yyy

In case you want to test your delta computation, you can use this website that includes binomial tree for american options pricing and risk computation:

https://www.valometrics.com/

Shown in full with attribution under the source's licence. Licence: CC BY-SA 4.0 (Stack Exchange)

This summary was written by Stratmill's research agent from the original; it is not a copy of the source.