Skip to content
All library documents

Equivalent Martingale Measures for a Vasicek Mean-Reverting Process

Article Quant Q&A · Author: bcf

Summary

The document compares the change-of-measure argument used to make a discounted asset price a martingale in Black–Scholes with the case of a mean-reverting Vasicek process. The question observes that discounting the Vasicek state variable does not produce the same multiplicative stochastic equation as discounted geometric Brownian motion and asks how to construct an equivalent martingale measure.

The response emphasizes a distinction in the models’ state spaces: geometric Brownian motion has positive support, while the Vasicek Ornstein–Uhlenbeck process can take values across the real line, including negative values. An equivalent measure preserves support, so the martingale measure need not have the exponential form associated with Black–Scholes. The answer suggests the proposed final expression may itself be a martingale, but does not work through a full measure change or pricing derivation. The discussion is therefore a conceptual clarification, not a complete recipe for selecting risk premia or pricing securities under Vasicek dynamics.

Key ideas

  • The Black–Scholes change of measure makes the discounted asset price a martingale through a drift adjustment.
  • A Vasicek process is mean reverting and can take negative as well as positive values.
  • Equivalent measures preserve the process’s support, so a Vasicek martingale measure need not resemble the Black–Scholes exponential construction.
  • The response questions whether the proposed discounted process is actually non-martingale but does not provide a complete derivation.

Tags

Full text
# Martingale Measure for Vasicek process


# Martingale Measure for Vasicek process












First, under Black-Scholes we have the usual method to transform the discounted asset price into a martingle: Let the asset price $S_t$ be goverend by $$ dS_t = \mu S_t dt + \sigma S_t dW_t, $$ so \begin{align*} d(e^{-rt}S_t) & = -re^{-rt}S_tdt + e^{-rt}\left(\mu S_t dt + \sigma S_t dW_t\right) \\ & = \sigma e^{-rt}S_t\left( \frac{\mu - r}{\sigma}dt + dW_t \right). \end{align*} Set $\gamma = \frac{\mu - r}{\sigma}$ and let $\tilde{W}_t = W_t + \gamma t$, a $\mathbb{Q}$-BM. We then get that our discounted asset price process is a $\mathbb{Q}$-martingale, and we can begin pricing options: $$ d(e^{-rt}S_t) = \sigma e^{-rt}S_t d\tilde{W}_t. $$

Now, what if the asset price is goverened by some other SDE, e.g. a mean-reverting process given by the SDE $$ dS_t = \kappa(\theta - S_t)dt + \sigma dW_t. $$ Following the same method as above, I get \begin{align*} d(e^{-rt}S_t) & = -re^{-rt}S_tdt + e^{-rt}\left(\kappa(\theta - S_t)dt + \sigma dW_t\right) \\ & = e^{-rt}\left[(\kappa(\theta - S_t) - rS_t)dt + \sigma dW_t \right]. \end{align*} The problem here is this SDE for the discounted asset price is not in terms of the disounted price itself, i.e., there is no explicit $e^{-rt}S_t$ multiplying the RHS. Hence, even using the closed-form solution for $S_t$ and letting $\gamma = \frac{\kappa(\theta - S_t) - rS_t}{\sigma}$ (again $\tilde{W}_t = W_t + \gamma t$), we get $$ d(e^{-rt}S_t) = \sigma e^{-rt}\tilde{W}_t, $$ which is not a martingale in the variable $e^{-rt}S_t$ as needed. Is there a framework for these sort of mean-reverting processes?

## Answer by Kiwiakos (score 3)

https://quant.stackexchange.com/a/17800

I think that you are a bit confused: the support of the Black-Scholes model is $(0,+\infty)$, that is to say the underlying asset price is non-negative, like a stock.

The Vasicek model has an OU process whose support is $(-\infty,+\infty)$, that is to say the underlying can be negative. Therefore all equivalent measures (of which the martingale is one) must have the whole line as support.

Therefore the Vasicek equivalent martingale cannot not have the same form as the BS exponential martingale, which is what you seem to be after. However, your last expression looks like a martingale to me, why do you say that it is not?

Shown in full with attribution under the source's licence. Licence: CC BY-SA 4.0 (Stack Exchange)

This summary was written by Stratmill's research agent from the original; it is not a copy of the source.