Estimating CAPM Alpha and Beta for an Equally Weighted Portfolio
Summary
The document considers whether the CAPM regression alpha and beta of an equally weighted portfolio can be found by averaging the corresponding estimates for its constituents. For assets measured over the same observations against a common benchmark and risk-free rate, the regression slope and intercept are linear in returns, so the portfolio estimates equal the weight-adjusted averages of constituent estimates. The derivation uses ordinary least squares and the portfolio return identity.
It distinguishes empirical regression estimates from the theoretical CAPM, which predicts zero alpha, and notes that observed nonzero alphas can be tested. The discussion assumes aligned observations and a shared market factor; assets in different countries may require different benchmarks, which makes a single-factor portfolio regression less straightforward. It also cautions that one year of monthly data is limited for estimating coefficients and that mechanically compounding monthly alpha does not by itself establish a valid annual performance estimate. The answers differ in emphasis, so assumptions matter.
Key ideas
- For a common benchmark and aligned return observations, an equally weighted portfolio beta is the average of constituent regression betas.
- Under the same conditions, the portfolio regression alpha is the average of constituent regression alphas.
- The theoretical CAPM predicts zero alpha, while empirical regressions may estimate nonzero intercepts.
- Cross-country assets may not share a suitable benchmark, limiting the direct averaging result.
- A short monthly sample can make coefficient estimates imprecise, and alpha compounding needs careful interpretation.
Tags
Full text
# Calculate alpha (CAPM) in "cross country-portfolio"
# Calculate alpha (CAPM) in "cross country-portfolio"
Assume I wanted to compute the alpha (in CAPM sense, i.e. $r_i - r_f = \alpha_i + \beta_i(r_m - r_f) + \epsilon_i$) of a stock. So I take, say, monthly returns of a stock $i$ for 1 year. Subtract the riskfree rate from this and call this $Y_i$. Now I take the corresponding benchmarket return and similarly i subtract the risk free rate from this and call it $X_i$. Now, to compute $\alpha_i$ I perform a linear regression for the model: $Y_i=\alpha_i + \beta_i X_i + \epsilon_i$
Now, if I wanted to compute $\alpha$ for an equally weighted portfolio of stocks listed on different exchanges in different countries (assume risk free rate equal). Then we have the portfolio return $$r_p = \frac{1}{n}\sum_{i=1}^{n}r_i = \\\frac{1}{n}\sum_{i=1}^{n}(r_f + \alpha_i + \beta_i(r_m-r_f)) = \\r_f + \frac{1}{n}\sum_{i=1}^{n}\alpha_i + \frac{1}{n}\sum_{i=1}^{n}\beta_i (r_m-r_f)$$ Can I now say that $\alpha_p = \frac{1}{n}\sum_{i=1}^{n}\alpha_i$ and $\beta_p=\frac{1}{n}\sum_{i=1}^{n}\beta_i$?
(Here $r_m$ is the benchmark for each corresponding asset, I didn't use a notation for this though..)
Also, if the portfolio strategy is a buy-and-hold with horizon 1 year before being balanced and the alphas are monthly, is it safe to annualize them in the most naive manner $(1+\alpha)^{12}-1$?
## Answer by antonio (score 1, accepted)
https://quant.stackexchange.com/a/11338
#### Error term
The error term tells the difference between the theoretical and the observed values of the dependent variable. As such it is referred to the single observations. In your equation, as you say, $i$ stands for the $i$-th share, therefore the meaning of $\varepsilon_i$ is unclear (as it can't be the $i$-th observation) and the related equations too. Perhaps you should add to the given equation(s) a second index, say $j$, related to the $j$-th observation.
#### CAPM and alpha
There is a problem with your question in that the CAPM assumes alphas to be zeros. Your claims is trivially true since the average of many zeros will still be zero, but perhaps this is not what you are looking for.
#### CAPM test
CAPM assumptions can be violated, therefore one might want to test whether in actual markets the share alphas are zeros or not. When alphas are not zero, you may wonder what is the relation between their value with respect to a portfolio and its single constituents.
#### Portfolio alpha with a linear model
Consider a generic linear model relating a portfolio and the market return in excess of the risk-free rate: $$ r_{pj} -r_f = \alpha_p + \beta_p (r_{mj} -r_f ) + \varepsilon_{pj} $$ where the equation is related to the $j$-th observation of the portfolio and market excess return.
The same model with respect to the $i$-th portfolio constituent is: $$ r_{ij} -r_f = \alpha_i + \beta_i (r_{mj} -r_f ) + \varepsilon_{ij} $$ The portfolio is equally weighted, therefore (for each $j$-th observation) \begin{align} r_{pj}=\frac{1}{n}\sum_j^n r_{ij} \tag{*}\label{*} \end{align} By means of some statistical methods one can find the estimated alphas and betas, that is the "best" $\alpha_*, \beta_*$ to minimise the $\varepsilon$-errors between theoretical and observed return values. This is normally found solving: $$\min_{\alpha_i,\,\beta_i} \sum_{j=1}^n \hat{\varepsilon}_{ij}^{\,2} = \min_{\alpha_i,\,\beta_i} \sum_{j=1}^n \left( r_{ij} -r_f - \alpha_i - \beta_i (r_{mj} -r_f ) \right) $$ and $$\min_{\alpha_p,\,\beta_p} \sum_{j=1}^n \hat{\varepsilon}_{pj}^{\,2} = \min_{\alpha_p,\,\beta_p} \sum_{j=1}^n \left( r_{pj} -r_f - \alpha_p - \beta_p (r_{mj} -r_f ) \right) $$ For a general linear model, $ y = \alpha + \beta x$, the solution (estimator) is known to be (see for example here): \begin{align} \tag{**}\label{**} \hat\beta = \frac{ \sum\limits_{j=1}^{N} (x_{j}-\bar{x})(y_{j}-\bar{y}) }{ \sum\limits_{j=1}^{N} (x_{j}-\bar{x})^2 } \end{align} where $\bar{*}$ is the sample mean, e.g. (replacing summation dummy to avoid name clash): $$ \bar{x}=\frac{1}{N}\sum_h^N x_h $$ Substituting to \eqref{**} our excess returns, with respect to the $i$-th share beta, we get: \begin{align} \hat\beta_i &= \frac{ \sum\limits_{j=1}^{N} \left( r_{mj} -r_f - \frac{1}{N}\sum\limits_h^N (r_{mh} -r_f) \right) \left( r_{ij} -r_f - \frac{1}{N}\sum\limits_h^N (r_{ih} -r_f) \right) } { \sum\limits_{j=1}^{N} \left( r_{mj} -r_f -\frac{1}{N}\sum\limits_h^N (r_{mh} -r_f) \right)^2 } \notag\\ &=\frac{ \sum\limits_{j=1}^{N} \left( r_{mj} - \frac{1}{N}\sum\limits_h^N r_{mh} \right) \left( r_{ij} - \frac{1}{N}\sum\limits_h^N r_{ih} \right) } { \sum\limits_{j=1}^{N} \left( r_{mj} -\frac{1}{N}\sum\limits_h^N r_{mh} \right)^2 } \notag \end{align} As for the portfolio beta, we have: \begin{align} \hat\beta_p &=\frac{ \sum\limits_{j=1}^{N} \left( r_{mj} - \frac{1}{N}\sum\limits_h^N r_{mh} \right) \left( r_{pj} - \frac{1}{N}\sum\limits_h^N r_{ph} \right) } { \sum\limits_{j=1}^{N} \left( r_{mj} -\frac{1}{N}\sum\limits_h^N r_{mh} \right)^2 } \notag \end{align} Replacing the portfolio return definition from \eqref{*}, we obtain: \begin{align} \hat\beta_p &=\frac{ \sum\limits_{j=1}^{N} \left( r_{mj} - \frac{1}{N}\sum\limits_h^N r_{mh} \right) \left( \frac{1}{n}\sum\limits_i^n r_{ij} -\frac{1}{N}\sum\limits_h^N \frac{1}{n}\sum\limits_i^n r_{ih} \right) } { \sum\limits_{j=1}^{N} \left( r_{mj} -\frac{1}{N}\sum\limits_h^N r_{mh} \right)^2 } \notag\\ &=\frac{ \sum\limits_{j=1}^{N} \left( r_{mj} - \frac{1}{N}\sum\limits_h^N r_{mh} \right) \frac{1}{n}\sum\limits_i^n \left( r_{ij} -\frac{1}{N}\sum\limits_h^N r_{ih} \right) } { \sum\limits_{j=1}^{N} \left( r_{mj} -\frac{1}{N}\sum\limits_h^N r_{mh} \right)^2 } \notag\\ &= \frac{1}{n}\sum\limits_i^n \frac{ \sum\limits_{j=1}^{N} \left( r_{mj} - \frac{1}{N}\sum\limits_h^N r_{mh} \right) \left( r_{ij} -\frac{1}{N}\sum\limits_h^N r_{ih} \right) } { \sum\limits_{j=1}^{N} \left( r_{mj} -\frac{1}{N}\sum\limits_h^N r_{mh} \right)^2 } = \frac{1}{n}\sum\limits_i^n \hat\beta_i \notag \end{align}
As for alpha the general estimator, this is: $$ \hat\alpha = \bar{y} - \hat\beta\,\bar{x} $$ Therefore: $$ \hat\alpha_i = \frac{1}{N}\sum\limits_h^N (r_{ih} -r_f) - \hat\beta_i\,\frac{1}{N}\sum\limits_h^N (r_{mh} -r_f) $$ and $$ \hat\alpha_p = \frac{1}{N}\sum\limits_h^N (r_{ph} -r_f) - \hat\beta_p\, \frac{1}{N}\sum\limits_h^N (r_{mh} -r_f) $$ Replacing the portfolio return definition from \eqref{*}: \begin{align} \hat\alpha_p &= \frac{1}{N}\sum\limits_h^N \left(\frac{1}{n}\sum\limits_i^n r_{ih} -r_f\right) - \frac{1}{n}\sum\limits_i^n \hat\beta_i \frac{1}{N}\sum\limits_h^N (r_{mh} -r_f) \notag\\ &= \frac{1}{N}\sum\limits_h^N \frac{1}{n}\sum\limits_i^n \left( r_{ih} -r_f\right) - \frac{1}{n}\sum\limits_i^n \hat\beta_i \frac{1}{N}\sum\limits_h^N (r_{mh} -r_f) \notag\\ &= \frac{1}{n}\sum\limits_i^n \left( \frac{1}{N}\sum\limits_h^N ( r_{ih} -r_f ) - \hat\beta_i \frac{1}{N}\sum\limits_h^N (r_{mh} -r_f)\right) = \frac{1}{n}\sum\limits_i^n \hat\alpha_i \notag \end{align}
This is just to give you a general idea of the problem.
## Answer by DerekT (score 2)
https://quant.stackexchange.com/a/11328
Basically you have two equations as follows: -Regression:
$$R_i = α + β \cdot R_m + e_i$$ -CAPM equation:
$$E(R_i) = r_f + β\left[E(R_m) - r_f\right]$$
In CAPM sense, there is no α . It only exists as idiosyncratic return.
You would need lot more than one year of data to estimate the coefficients for regression. You can check p-values to see if the coefficients are significant ie less than or equal to .05. Since you will be doing the multivariate OLS your data requirement will increase even more.
Actually your portfolio consisting of equal weights of securities can mislead thinking. Remember there is diversification effects in a portfolio; portfolio volatility will be smaller, beta of the portfolio will also change. This will lead to a different alpha at the portfolio level. In other words, you cannot just average the alpha of assets to get portfolio alpha.Shown in full with attribution under the source's licence. Licence: CC BY-SA 4.0 (Stack Exchange)
This summary was written by Stratmill's research agent from the original; it is not a copy of the source.