Estimating CAPM Beta With or Without an Intercept
Summary
The document distinguishes the CAPM’s expected-return prediction from statistical estimation of beta using realized returns. Regressing excess security returns on excess market returns through the origin imposes a zero alpha and produces a slope based on their uncentered second moments. Including an intercept instead estimates beta from covariance divided by market excess-return variance.
The accepted answer cautions that imposing zero alpha can make estimates less robust when the factor model is misspecified, so empirical researchers commonly retain an intercept. It also explains that the familiar covariance-to-variance beta on raw returns follows only under assumptions such as a nonrandom risk-free rate. A second response stresses that CAPM is a theoretical relation among expected returns, distinct from the regression used to estimate an asset’s beta; the model’s empirical limitations remain a caveat.
Key ideas
- A regression through the origin imposes the restriction that alpha is zero.
- With an intercept, beta is covariance of excess returns divided by the variance of market excess returns.
- The raw-return covariance formula requires assumptions about the risk-free rate.
- CAPM’s expected-return prediction and the empirical regression used to estimate beta are separate concepts.
- Restricting alpha can reduce robustness when a factor model is misspecified.
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Full text
# CAPM model as a regression
# CAPM model as a regression
The CAPM model states that the returns of a stock are-
$r_s=r_f+\beta (r_m-r_f)+\varepsilon_s$
The $\beta$ defined above is then calculated as $\frac{cov(r_s,r_m)}{var(r_m)}$. My question is regarding this formula. This is the regression coefficient if the intercept is NOT set to 0, which is not the case in CAPM since the intercept is set to a constant $r_f$, which is essentially regressing $r_s-r_f$ against $r_m-r_f$ while setting the intercept to 0. That should yield $\beta=\frac{E[(r_s-r_f)(r_m-r_f)]}{E[(r_m-r_f)^{2}]}$, which is not equal to the canonical form.
Please let me know what is the issue here.
## Answer by Matthew Gunn (score 9, accepted)
https://quant.stackexchange.com/a/39127
If you really believed the CAPM's prediction that $\alpha=0$, then imposing $\alpha=0$ in your estimation would indeed lead to your 2nd formula.
The problems?
- The CAPM doesn't work so imposing a false restriction during estimation is problematic.
- More generally, taking factor models extremely seriously and imposing $\alpha=0$ in estimation to gain efficiency loses you some robustness because factor models are almost certainly at least somewhat misspecified.
Empirical researchers generally don't restrict a constant to zero during estimation.
#### Model 1 (without a constant):
Let's assume we have the following regression model (without a constant):
$$ r_{st} - r_{ft} = \beta_1 \left( r_{mt} - r_{ft} \right) + \epsilon_t$$
Assuming the orthogonality condition $\operatorname{E}\left[\epsilon_t \left( r_{mt} - r_{ft}\right)\right] = 0$, then $\beta_1$ would be given by:
$$ \beta_1 = \frac{\operatorname{E}\left[\left( r_{st} - r_{ft} \right)\left(r_{mt} - r_{ft} \right) \right] }{\operatorname{E}\left[\left(r_{mt} - r_{ft}\right)^2\right]}$$
If you really take the CAPM theory seriously, then there is something principled to imposing the restriction $\alpha= 0$ in estimation (which is what we did above). Quoting Cochrane (2004) with regards to more general factor models with normally distributed errors, "The maximum likelihood estimate of $\beta$ is the OLS regression without a constant." As Cochrane describes though, researchers don't generally estimate without a constant because it sacrifices some robustness.
#### Model 2 (add a constant):
$$ r_{st} - r_{ft} = \alpha_2 + \beta_2 \left( r_{mt} - r_{ft} \right) + \epsilon_t$$
Now with $\alpha_2$ there and assuming the orthogonality conditions $\operatorname{E}[\epsilon_t] = 0$ and $\operatorname{E}\left[\epsilon_t \left( r_{mt} - r_{ft}\right)\right] = 0$, you get:
$$ \beta_2 = \frac{\operatorname{Cov}\left( r_{st} - r_{ft} , r_{mt} - r_{ft} \right) }{\operatorname{Var}\left( r_{mt} - r_{ft} \right)}$$
Model 1 is a special case of Model 2 where $\alpha $ is restricted to 0.
#### Model 3 (if the risk free rate weren't random):
If the risk free rate isn't random then it drops out:
$$ \beta_3 = \frac{\operatorname{Cov}\left( r_{st}, r_{mt} \right) }{\operatorname{Var}\left( r_{mt} \right)}$$
In periods like the present where the risk free rate is constantly about 0, maybe this bogus assumption is innocuous. I think it's hand-wavy, intro MBA type stuff though.
### A comment on the CAPM
Be aware that the CAPM is a zombie theory: long ago shot dead in academia because it doesn't work, the CAPM continues to skulk the earth. Quoting Fama and French (2004), "... the empirical record of the model is poor—poor enough to invalidate the way it is used in applications."
#### References
Cochrane, John. 2005. Asset Pricing, p. 273
Fama, Eugene, F., and Kenneth R. French. 2005. "The Capital Asset Pricing Model: Theory and Evidence." Journal of Economic Perspectives, 18 (3): 25-46.
## Answer by Tim Wilding (score 0)
https://quant.stackexchange.com/a/39126
I am going to start off by saying that your initial equation is not the correct formulation for CAPM. It should be:
$E(r_s) = r_f + \beta (E(r_m) – r_f)$.
In other words, this is a relationship between the expected returns of the security and the expected returns of the market and is a prediction of the CAPM (the Security Market Line). Rewriting the equation like this highlights that there are two separate calculations here and the two should not be mixed.
In the first calculation, $\beta$ is the regression coefficient for a particular security’s returns ($r_s$) on the market returns ($r_m$). That $\beta$ is a function of our assumed distribution of security returns. Typically, it would be calculated using OLS from a time series of returns.
In the second calculation, the relationship between $\beta$ and the expected returns is a prediction of the CAPM. This prediction is only true if the CAPM theory applies and the benchmark is a proper representation of the market. In that case, $E(r_s) = r_f + \beta (E(r_m) – r_f)$. As you can see, this equation deals with the expected returns, whereas the calculation of $\beta$ deals with the full distribution of returns. Typically, you would estimate $E(r_m)-r_f$ by using a universe of securities and regressing their average returns on their $\beta$'s.
## Answer by linksideal (score -1)
https://quant.stackexchange.com/a/39093
If you do a linear regression like $r_s - r_f = \beta (r_m - r_f) $ Then $\beta$ is calculated as $\beta = \frac { Cov(r_m - r_f, r_s-r_f)}{var (r_m-r_f)} $. Using colinearity, and the fact that $r_f$ is not random yields $\beta = \frac{cov(r_s,r_m)}{var(r_m)}$.Shown in full with attribution under the source's licence. Licence: CC BY-SA 4.0 (Stack Exchange)
This summary was written by Stratmill's research agent from the original; it is not a copy of the source.