Estimating VaR and CVaR Sensitivity with Bump and Revaluation
Summary
The document asks how to differentiate Value-at-Risk and Conditional Value-at-Risk for a capped random variable, formed by taking the minimum of a random variable and a threshold. It does not derive the sensitivity or specify assumptions about the distribution, quantile convention, or treatment of points where the risk measure is not differentiable.
The answer gives a general numerical fallback: evaluate the risk measure at the current threshold and at a slightly increased threshold, then divide the change by the size of that bump. It advises using a closed-form derivative when one is available, since that can be faster. The finite-difference estimate depends on the bump size and may be inaccurate near discontinuities or where the measure is nonsmooth; the brief response provides no error analysis or worked example.
Key ideas
- A closed-form derivative is preferable when it can be obtained for the chosen risk measure.
- Bump and revaluation estimates sensitivity by changing the threshold slightly and measuring the resulting change in VaR or CVaR.
- Finite-difference accuracy depends on bump size and local smoothness.
- The discussion does not derive a formula or state distributional assumptions.
Tags
Full text
# Answer by MaPy (score 1)
# How to calculate $\frac{\partial\ \text{CVaR}_{\alpha}(\min(X,d))}{\partial d}$ and $\frac{\partial\ \text{VaR}_{\alpha}(\min(X,d))}{\partial d}$?
How to calculate $\frac{\partial\ \text{CVaR}_{\alpha}(\min(X,d))}{\partial d}$ and $\frac{\partial\ \text{VaR}_{\alpha}(\min(X,d))}{\partial d}$?
Here, $\text{CVaR}$ is short for Conditional Value-at-Risk and $\text{VaR}$ is short for Value-at-Risk. And $X$ is a random variable.
## Answer by MaPy (score 1)
https://quant.stackexchange.com/a/40782
It really depends on the way you calculate your Var and CvaR. If your are able to get a closed form solutions for the derivative then you must use those, for faster results. Otherwise, you can use bump and reval. $$\frac{\partial V}{\partial d} = \frac{V(d+h) - V(d)}{h}$$Shown in full with attribution under the source's licence. Licence: CC BY-SA 4.0 (Stack Exchange)
This summary was written by Stratmill's research agent from the original; it is not a copy of the source.