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How a Radon–Nikodym Measure Change Alters a Gaussian Distribution

Article Quant Q&A · Author: bcf

Summary

The document explains a probability measure change using an exponential tilt of a normally distributed random variable. A normalized exponential function of the variable serves as the Radon–Nikodym derivative, defining a new measure on the same measurable space. Under that measure, the variable remains the same mapping on the space, but its distribution is Gaussian with a shifted mean and unchanged variance.

The discussion addresses why this is often described as changing the distribution without changing the random variable, even though calculations under the original measure can represent the shifted law through a transformed variable. It connects this distinction to the Brownian motion adjustment used in Girsanov’s theorem in option pricing. The answer’s central point is that the descriptions depend on what is held fixed: changing measure changes the law of the same variable, while reproducing that law under the original measure can instead involve changing the variable. The note is conceptual and does not develop a pricing example or conditions for the measure change.

Key ideas

  • A normalized exponential tilt of a Gaussian variable defines a new probability measure.
  • Under the new measure, the same random variable has a shifted mean and the same variance.
  • Changing measure and transforming a random variable can describe equivalent probability calculations.
  • The distinction between these viewpoints appears in measure changes used in option pricing.

Tags

Full text
# Radon-Nikodym: Changing Distribution vs Changing Random Variable


# Radon-Nikodym: Changing Distribution vs Changing Random Variable












Let $X \sim \mathcal{N}(\mu,\sigma^2)$ under the probability measure $P$ on the measurable space $(\Omega, \mathcal{F})$. We may define a Radon-Nikodym derivative $Z$, also defined on $(\Omega, \mathcal{F})$, by $$ Z(\omega) := \frac{e^{\alpha X(\omega)}}{M_X(\alpha)} = \exp\left(\alpha X(\omega) - \alpha\mu - \frac{1}{2}\alpha^2\sigma^2\right) $$ for $\alpha \in \mathbb{R}$, where $M_X(\alpha) = \exp(\alpha\mu + \frac{1}{2}\alpha^2\sigma^2)$ is the MGF of $X$. The random variable $Z$ indeed qualifies as a Radon-Nikodym derivative, so let's use it to define a new probability measure $\tilde{P}$ on $(\Omega, \mathcal{F})$ by $$ \tilde{P}(A) := \int_A Z(\omega) \, dP(\omega) \qquad \text{for all } A \in \mathcal{F}. $$ It can be shown that, under $\tilde{P}$, $X \sim \mathcal{N}(\mu + \sigma^2\alpha, \sigma^2)$. In words, I've often seen this described (e.g. Shreve II, p. 37) as

> We changed the distribution of the random variable without changing the random variable itself.

However, computing probabilities of $X$ under $\tilde{P}$ is then equivalent to computing probabilities of $X + \sigma^2\alpha$ under $P$, in which we do change the random variable; we add $\sigma^2\alpha$ to it.

Even more, for option pricing, Shreve gives Grisanov's theorem on the bottom of p. 212, and defines a new random variable $$ \tilde{W}(t) = W(t) + \int_0^t \theta(u) \, du, $$ which is then substituted into the stock price model. So here, in its most applied context in quant finance, we are blatantly changing the random variable!

So, although the above quote about changing only the distribution is technically valid in one sense, in the other sense we really are changing the random variable. Am I missing something?

## Answer by Gordon (score 2, accepted)

https://quant.stackexchange.com/a/21958

When the measure is changed, the distribution of the same random variable is also changed. That is, under the new measure, you obtain a new distribution for the same random variable. However, while you hold the new distribution fixed and go back to the original measure, then the random variable has to be changed. If you do not take the new distribution, then you do not have to change the random variable. In other words, to have a new distribution, you can either change the measure or change the random variable.

Shown in full with attribution under the source's licence. Licence: CC BY-SA 4.0 (Stack Exchange)

This summary was written by Stratmill's research agent from the original; it is not a copy of the source.