How Continuous Dividends Affect Black–Scholes Call Values
Summary
The document compares Black–Scholes formulas for European calls on otherwise similar assets, one with a continuous dividend yield and one without. It identifies two changes in the dividend-paying formula: the spot-price term is discounted by the yield, and the yield lowers the rate used in the formula’s normal-distribution arguments. The question motivating the discussion is how to prove from the formulas that the dividend-paying call is worth less, since the changes to the two strike-related terms make a direct comparison less obvious.
The answer offers an intuition that dividends reduce the stock’s expected future value and thus the call’s upside. It does not provide a mathematical proof or resolve the comparison of the formula terms. Its explanation is qualitative, and the claim applies to the stated comparison with matching inputs and a nonnegative continuous dividend yield; it does not analyze other contract or market differences.
Key ideas
- The dividend yield discounts the spot-price component in the European call formula.
- The yield also changes the normal-distribution arguments by reducing the effective growth rate.
- The answer uses reduced expected stock value to explain why a dividend-paying call may be worth less.
- The document does not complete the requested algebraic proof.
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# Answer by Winodd Dhamnekar (score 1)
# Prove from Black-Scholes that value of a European call option on an asset that pays continuous dividends less than a call without dividends
Black-Scholes gives us the following formulae for the prices of European calls on an underlying that does or doesn't pay continuous constant dividends (of proportion $D$):
$$C^E_D(S_t,t,K,T)=e^{-D(T-t)}S_t\Phi(d_D)-e^{-r(T-t)}K\Phi(d_D-\sigma \sqrt{(T-t)})$$ $$C^E(S_t,t,K,T)=S_t\Phi(d)-e^{-r(T-t)}K\Phi(d-\sigma \sqrt{(T-t)})$$
Where $d_D=\frac{\text{ln}\left(\frac{S_t}{K}\right)+(r-D+\frac{1}{2}\sigma^2)(T-t)}{\sigma \sqrt{(T-t)}}$ and $d=\frac{\text{ln}\left(\frac{S_t}{K}\right)+(r+\frac{1}{2}\sigma^2)(T-t)}{\sigma \sqrt{(T-t)}}$.
Now I know from common sense and no-arbitrage reasoning that we must have $C^E_D<C^E$, but am struggling to see how the formulae show this. Can it be proven mathematically?
i.e. something along the lines of: $$d_D<d\Rightarrow \Phi(d_D)<\Phi(d)$$
But this decrease works against us on the $K$ term...
## Answer by Winodd Dhamnekar (score 1)
https://quant.stackexchange.com/a/78544
Here's how we can prove that the Black-Scholes price of a European call option on an asset that pays a continuous dividend is less than the Black-Scholes price of a European call option on a similar asset that doesn't pay any dividend.
Understanding the Black-Scholes Model
The Black-Scholes model provides a way to calculate the theoretical price of a European-style call or put option using the following input variables:
- S: Current stock price
- K: Exercise/Strike price
- T: Time to expiration (in years)
- r: Risk-free interest rate
- σ: Volatility of the underlying asset
- q: Continuous dividend yield
The Impact of Dividends
In the presence of continuous dividend payments, the expected stock price at any point in the future is reduced. Here's why:
- When a stock pays a dividend, its price immediately decreases (on the ex-dividend date) by an amount roughly equal to the dividend payment.
- This dividend payment represents a cash outflow from the company to shareholders, reducing the assets held by the company and thereby reducing its stock price.
Effect on the Black-Scholes Formula
The Black-Scholes formula for a European call option on a stock that pays a continuous dividend yield is:
$C = Se^{(-qT)} N(d_1) - Ke^{(-rT)} N(d_2)$
Where:
$d_1 = [\ln{(S/K)} + (r - q + \sigma^²/2)T] / (\sigma\sqrt{T})$
$d_2 = d_1 - \sigma\sqrt{T}$
N(x) is the cumulative standard normal distribution function
Notice the term $e^{(-qT)}$ which reduces the value of `S` in the formula as opposed to the Black-Scholes formula for a non-dividend paying stock, where this term doesn't exist.
The Result
Since dividends effectively reduce the future value of the underlying stock, the call option becomes less valuable for the option holder for the same strike price. The potential upside from the option exercising is reduced because the stock price is likely to be lower due to the dividend payments. Consequently, the price of the call option on a dividend-paying stock will be lower than the price of a similar call option on a non-dividend-paying stock.
Conclusion
The presence of a continuous dividend yield reduces the price of a European call option, as calculated by the Black-Scholes model, compared to an identical option on a stock that doesn't pay any dividends.Shown in full with attribution under the source's licence. Licence: CC BY-SA 4.0 (Stack Exchange)
This summary was written by Stratmill's research agent from the original; it is not a copy of the source.