How Markov and Martingale Processes Differ in GBM Pricing
Summary
The document distinguishes three ideas used in asset pricing. A Markov process has future distributions that depend on the current state rather than the full path of past states. A martingale has a conditional expected future value equal to its current value, given the available history. These properties are different: a process can have either, both, or neither.
Geometric Brownian motion is presented as a Markov process whose drift determines whether the process itself is a martingale: under the stated model, it is a martingale when its drift is zero. The responses also give examples of processes that satisfy one property but not the other. For pricing, the probability measure matters: discounted asset prices are martingales under a risk-neutral measure with the money-market account as numeraire, but need not be martingales under the real-world measure. The explanations are introductory and omit technical conditions such as integrability; they do not develop option-pricing calculations.
Key ideas
- The Markov property says the current state captures the information in the past that matters for future distributions.
- The martingale property says the conditional expected future value equals the current value.
- Markov and martingale are distinct properties, and a process may have either, both, or neither.
- In the stated geometric Brownian motion model, the process is a martingale only when its drift is zero.
- Whether discounted prices are martingales depends on the probability measure used.
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# Understanding the concept of Martingale pricing
# Understanding the concept of Martingale pricing
I am a bit confused about how to formulate a problem where I have to price an option on a stock. Many papers say that stock prices are best modeled using a geometric Brownian motion (GBM), and I understand that GBM is a Markov process. But i have recently read about Martingales and I am confused. Are stock prices modeled as GBM or martingales? Is a martingale a special type of GBM where drift is zero?
Can you please explain to me in detail and in basic language the relation and differences between Markov, GBM, and Martingale processes. And can you please provide me with an example, starting with a GBM, and how to derive a Martingale process from that?
Thank you very much!!
## Answer by HardyHulley (score 9)
https://quant.stackexchange.com/a/9472
Roughly speaking, we can express the difference between a Markov process and a martingale as follows:
- A Markov process is one for which conditioning its future value on its history is the same as conditioning its future value on its present value, so that $E(h(X_t)\,|\,X_u,\,u\leq s)=E(h(X_t)\,|\,X_s)$, for any appropriate function $h$;
- A martingale is a process whose expected future value equals its present value, when conditioned on its history, so that $E(X_t\,|\,X_u,\,u\leq s)=X_s$,
for all $s\leq t$. (Note that I am taking huge liberties by ignoring integrability conditions and other important caveats.)
In words, we might say that Markov processes have the property that their histories provide no information in excess of the information contained in their present values. Similarly, we might say that martingales are processes for which the best estimate of their future value is their current value.
These two concepts have an interesting history in Financial Economics. For example, the Efficient Market Hypothesis effectively asserts that asset price processes are Markov. On the other hand, much of Asset Pricing Theory characterises fair value for risky securities in terms of martingales, in one way or another.
To answer your question, although both the Markov condition and the martingale condition are expressed in terms of conditional expectations, they are in fact quite different notions. In particular, processes can be (1) Markov processes and martingales; (2) Markov processes but not martingales; (3) martingales but not Markov processes; and (4) neither martingales nor Markov process. A good exercise is to construct examples of all four types of process listed above (focus on discrete-time, rather than continuous-time).
Geometric Brownian motion is a process $X$ characterised by the stochastic differential equation $$d X_t=\mu X_t\,dt+\sigma X_t\,d B_t,$$ for all $t\geq 0$, where $B$ is a standard Brownian motion. It is always Markov (incidentally, this explains why the price of an option written on a security that follows a geometric Brownian motion is a function of the current price of the security, and not its price history). However, $X$ is only a martingale when $\mu=0$ (in which case we refer to it as driftless geometric Brownian motion.
## Answer by wsw (score 3)
https://quant.stackexchange.com/a/9536
Just to give you two examples. Note that
- $dX_t =a \; dt + dW_t$ is Markov but is not a martingale.
- $dX_t=(\int_0^t X_s ds) \; dW_t$ is a martingale but is not Markov.
## Answer by jensa (score 3)
https://quant.stackexchange.com/a/9538
You have been given good answers above. Basically, a stochastic process ${X_t}$ is a Markov process if $P(\{X_{t} \leq x\} | \mathcal{F}_{s}) = P(\{X_{t} \leq x\} | X_{s})$, for $s \leq t$. Here $\mathcal{F}_{s}$ is a $\sigma$-algebra, a special collection of subsets of the underlying sample space $\Omega$, containing all information about the process $\{X_t\}$ up to $s$. In words this means that the distribution of the future values of $\{X_t\}$ does not depend on the path taken up to time $s$, but only on the value of $X$ at time $s$, i.e. $X_s$.
A martingale must be defined in terms of conditional expectations. A process $\{Y_t\}$ is a martingale with respect to the filtation $(\mathcal{F}_{t})_{t \geq 0}$ if $E\{Y_{t+h} | \mathcal{F}_{t}\} = Y_{t}$, for all $h \geq 0$. The best prediction of $Y_{t+h}$ given all information up to time $t$ is $Y_t$.
To connect this to your question on GBMs, if $dX_{t} = \mu X_t dt + \sigma X_t dB_t$, then $X_{t} = X_{0}e^{(\mu - \sigma^{2}/2)t + \sigma B_t}$. Solutions to stochastic differential equations are Markov Processes.
The martingale property depends on the probability measure. Discounted stock prices are martingales under the risk-neutral measure (using the money-market account as numérarie), but discounted stock prices are not martingales under the real-world probability measure.Shown in full with attribution under the source's licence. Licence: CC BY-SA 4.0 (Stack Exchange)
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