How Replication Supports the No-Arbitrage Price of a Call
Summary
The document discusses the no-arbitrage argument that a European call’s initial price should equal the cost of a replicating portfolio made from shares and a risk-free asset. The question focuses on an apparent inconsistency: if the option price exceeds the replication cost, selling the option and buying the replicating portfolio seems to leave a positive balance, despite the proof describing a zero-cost portfolio.
The response resolves the confusion by pointing out that replication may require borrowing to finance the share position. When borrowing and lending occur at the same rate, the apparent excess balance is not a free profit; financing must be included in the portfolio accounting. The exchange gives a concise conceptual clarification rather than a full derivation, and it assumes frictionless financing at a common rate. It does not address transaction costs, funding spreads, or practical replication errors.
Key ideas
- A call option can be valued by comparing it with a portfolio that replicates its payoff.
- The no-arbitrage argument depends on accounting for all financing in the replicating portfolio.
- Borrowing to fund shares offsets the apparent excess cash under the stated equal-rate assumption.
- Different borrowing and lending rates or trading frictions can complicate the simple argument.
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Full text
# Basic Replication of European Call Option
# Basic Replication of European Call Option
I am looking at the very basics of replicating an option with a portfolio of risky and risk free assets. As such we can define a portfolio of $x$ no. of shares, $y$ bonds & $z$ options at time $(T)$ as;
\begin{equation} V(T) = xS(T) + yA(T) +zC(T) \end{equation}
I understand that due to the No-Arbitrage Principle that there is:
> No portfolio that includes a position $z$ in call options and has initial value $V(0) = 0$ such that $V(T) \geq 0$ with probability 1 and $V(T) > 0$ with non-zero probability.
In the textbook we are then presented the value of an option to be;
> $C(0) = x S(0) + yA(0)$
Or else arbitrage could occur.
I have completed exercises on this and understand the principle/procedures in real life that would lead to this opportunity, however the proof of this equality then takes the form of supposing:
> $C(0) > xS(0) + yA(0)$
- We issue and sell one option for $C(0)$
- Take a long position in the equivalent portfolio $(x,y)$, i.e. buying shares and borrowing cash for replication of a call option
We thus have a positive balance of $C(0) -xS(0) - yA(0) > 0$ and invest this excess amount risk free.
The point I take objection with then follows in the assertion that the resulting portfolio then has an initial value of $V(0) = 0$, as if we were to sub this into our first equation, we would obviously end up with a non zero positive value due to our excess balance given by the inequality. I would also assume we can't just look at the $(x,y)$ portion of the portfolio following the definition given in the first quote block?
I understand I am probably missing a very basic concept in trying to understand this but it is annoying me enough that I wish to understand before progressing. If anyone can clear this up for me it would be greatly appreciated.
Cheers!
## Answer by Charles Fox (score 2)
https://quant.stackexchange.com/a/41911
There is no excess balance. As you stated, call option replication includes borrowing to fund the stock purchase. If you borrow and lend at the same interest rate, there is no profit.Shown in full with attribution under the source's licence. Licence: CC BY-SA 4.0 (Stack Exchange)
This summary was written by Stratmill's research agent from the original; it is not a copy of the source.