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How Skewness and Kurtosis Scale When Returns Are Aggregated

Article Quant Q&A · Author: Bob Jansen

Summary

The document explains how higher distributional moments change when independent, identically distributed log returns are added over time. Log returns are used because they add across periods, unlike simple returns. The method relies on two cumulant properties: cumulants add for sums of independent variables, and a cumulant of order k scales by the kth power when the variable is rescaled.

For a sum normalized by the square root of the number of periods to keep variance constant, the kth cumulant scales as n to the power 1 minus k/2. This gives skewness a 1 over square root of n rate and excess kurtosis a 1 over n rate, with the pattern extending to higher orders. The explanation is an analytical derivation, not an empirical test. Its scaling claims depend on IID returns and finite moments; dependence, changing distributions, or a different normalization can alter the result. The opening reference to the law of large numbers is less precise than the cumulant argument, which specifically analyzes normalized sums.

Key ideas

  • Log returns add across time, making them suitable for analyzing temporal aggregation.
  • Cumulants of independent sums add, while rescaling a variable scales its kth cumulant by the scale factor raised to k.
  • Normalizing an IID sum by the square root of its length holds its variance constant.
  • Under this normalization, skewness decays as 1 over square root of n and excess kurtosis as 1 over n.
  • The cumulant scaling formula extends to higher orders under the IID assumptions.

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Full text
# Skewness and Kurtosis under aggregation


# Skewness and Kurtosis under aggregation












Returns possess non-zero skewness and excess kurtosis. If these assets are temporally aggregated both will disappear due to the law of large numbers. To be exact, if we assume IID returns skewness scales with $\frac{1}{\sqrt{n}}$ and kurtosis with $\frac{1}{n}$.

I'm interested in a concise, clear and openly accessible proof for the above statement preferably for all higher moments.

This question is inspired by this question by Richard which deals with, among other things, the behaviour of the higher moments of returns under temporal aggregation. I know about two papers that answer this question. Hawawini (1980) is wrong and Hon-Shiang and Wingender (1989) is behind a paywall and a bit inscrutable.

## Answer by JL344 (score 24, accepted)

https://quant.stackexchange.com/a/3678

Just to be painfully clear, it only seems to make sense to consider the logarithm of returns, i.e. $X=\log (1+\frac r{100})$ for a simple return of $r\%$ in an arbitrary period because this is what sums when returns are temporally aggregated. A basic property of cumulants is that cumulants of all orders are additive under convolution, for which a proof can be found here here.

So if $X_1$, $X_2$, ... $X_n$ are i.i.d., then all the cumulants of $$Y_n = \sum_{i=1}^nX_i$$ scale linearly with $n$, i.e. $$\kappa_k(Y_n)=n\kappa_k(Y_1).$$ However, I suspect that you are normalizing this sum so that the variance (or volatility) remains constant with increasing $n$. So instead let us consider $$Z_n=\frac{Y_n}{\sqrt n}= \frac 1 {\sqrt n} \sum_{i=1}^nX_i.$$ Another basic property of cumulants is that the $k$th cumulant is homogeneous of order $k$ as to scale. Using both properties together we have $$\kappa_k(Z_n)=\left(\frac 1 {\sqrt n}\right)^k\kappa_k(Y_n)=\left(\frac 1 {\sqrt n}\right)^kn\kappa_k(Y_1)=\frac {\kappa_k(Z_1)}{n^{(k-2)/2}}.$$

(Don't forget that $Z_1=Y_1=X_1$.) Now we can show that the statistics scale as you have described: $$\textrm{variance}=\kappa_2(Z_n)=\kappa_2(Z_1)\propto 1;$$ $$\textrm{skewness} =\frac{\kappa_3(Z_n)}{\kappa_2(Z_n)^{3/2}}=\frac{\frac{1}{n^{1/2}}\kappa_3(Z_1)}{\kappa_2(Z_1)^{3/2}}\propto \frac 1{\sqrt n};$$ $$\textrm{ex. kurtosis}=\frac{\kappa_4(Z_n)}{\kappa_2(Z_n)^2}=\frac{\frac{1}{n}\kappa_4(Z_1)}{\kappa_2(Z_1)^{2}}\propto \frac 1 n.$$

There is no reason this cannot be extended to higher orders, although it works out more directly in terms of cumulants than of moments.

Shown in full with attribution under the source's licence. Licence: CC BY-SA 4.0 (Stack Exchange)

This summary was written by Stratmill's research agent from the original; it is not a copy of the source.