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Interpreting Left Limits in Jump-Diffusion Price Dynamics

Article Quant Q&A · Author: AlmostSureUser

Summary

The document explains a notation issue in a jump-diffusion stock model. The price follows continuous Brownian movements between jumps and changes discontinuously when a Poisson event occurs. At a jump time, the left limit denotes the price immediately before the jump, while the ordinary value denotes the price after it; the jump size is applied to the pre-jump value.

The accepted explanation says the two drift expressions are reconciled by recognizing that the price and its left limit agree away from jump times. It also rewrites the equation in terms of the pre-jump price. The key lesson is to preserve left-limit notation where jumps occur and interpret stochastic differentials using càdlàg paths. The discussion is a conceptual clarification rather than a derivation of jump-diffusion properties, and it does not address parameter estimation, pricing, or applications to trading.

Key ideas

  • At jump times, the price after the event differs from its left limit immediately before the event.
  • Between jumps, continuity of the Brownian component means the price and its left limit coincide.
  • Jump terms use the pre-jump price to scale the discontinuous change.
  • Càdlàg path conventions explain why left-limit notation matters in jump models.

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Full text
# Simple question on jump-diffusion


# Simple question on jump-diffusion












In the textbook by Shreve in sec. 11.7.2 a jump-diffusion process is introduced. More precisely

$$ dS_t = \alpha\,S_t\,dt+\sigma\,S_t\,dW_t+S_{t-}\,d\left(Q_t-\beta\,\lambda\,t\right)\quad (1) $$

where $Q_t = \sum_{i=1}^{N_t}Y_i$ and $N_t$ is Poisson with intensity $\lambda$. The process is re-written as

$$ dS_t = (\alpha-\beta\,\lambda)\,S_t\,dt+\sigma\,S_t\,dW_t+S_{t-}\,dQ_t\quad(2). $$

The problem is that, a part from time instants in which there is no jump and hence $S_t=S_{t-}$, I cannot go from (1) to (2), because if there is a jump of size $Y_i$ at time $t$ it holds that

$$ \frac{S_t-S_{t-}}{S_{t-}} = Y_i\rightarrow S_t = S_{t-}\,(Y_i+1). $$

and so I get

$$ dS_t = \alpha\,S_t\,dt+\sigma\,S_t\,dW_t+S_{t-}\,dQ_t-S_{t-}\,\beta\,\lambda\,dt\neq (\alpha-\beta\,\lambda)\,S_t\,dt+\sigma\,S_t\,dW_t+S_{t-}\,dQ_t. $$

Here there is a snapshot of the textbook.

## Answer by Quantuple (score 2, accepted)

https://quant.stackexchange.com/a/25288

Could it be that your problem is only due to the $t^-$ notation convention?

Think of it that way, it is only worth distinguishing $S_{t^-}$ from $S_t$ at a jump time. Elsewhere, knowing that Brownian motion paths are continuous, you'll always have $S_t = S_{t^-}$.

Thus you could also write the SDE:

$$\frac {dS_t}{S_{t^-}} = \alpha dt+\sigma dW_t+ d\left(Q_t-\beta\,\lambda\,t\right)$$

Or simply drop the $t^-$ notation altogether if it bothers you. Just remember that we are dealing with processes with càdlàg paths (right continuous $S_t $, left limit $S_{t^-} $)

Shown in full with attribution under the source's licence. Licence: CC BY-SA 4.0 (Stack Exchange)

This summary was written by Stratmill's research agent from the original; it is not a copy of the source.