Interpreting Theoretical Option Prices and Arbitrage
Summary
The document explains what a model-based option value means and when a difference between that value and a quoted market price implies arbitrage. In a one-step binomial setup, the option can be replicated with stock and borrowing; if the observed call price exceeds the replicating cost, selling the option and buying the hedge locks in a profit, assuming the model’s inputs and trading conditions hold.
The key qualification is that a model price is conditional on its assumptions, including the specified risk-neutral distribution. In real markets that distribution is not known precisely, so a model-versus-market gap alone does not establish a risk-free trade. The answer contrasts this with put-call parity violations, which can imply arbitrage without relying on a forecast of the underlying’s distribution, provided the parity instruments can be traded and financed as assumed. The example is conceptual: model error, transaction costs, funding, and execution constraints can undermine practical replication.
Key ideas
- A binomial model gives a conditional price based on its specified assumptions and inputs.
- Replication makes a model price relevant to arbitrage when the hedge matches the option payoff.
- A model-market price difference is not automatically risk-free when the underlying distribution is uncertain.
- Put-call parity violations can reveal arbitrage without specifying a return distribution.
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# Option pricing models relation between theoretical and actual price # Option pricing models relation between theoretical and actual price I have trying to figure out the relationship between theoretical option price and actual market price spotted from market which is determined by supply and demand. I yet cannot understand how to interpret that "theoretical price" which is given by for example binomial option pricing model. In what kind of world that is the the "true option price"? Does this mean, that if all assumptions HOLDS in real world, the true price should be the theoretical option price given by model and reflect the price spotted on market? And if there is mispricing, ie. the market price deviates from price given by model, there is chance for arbitrage because if assumptions hold, the price will drive up/down to the theoretical price and one could make arbitrage profit in theory. As illustrate my confusion, let take the example, where binomial option pricing model is used to price option with these details: Let S=$100, K=$95,r=8%,T =0.5,and δ=0.Let u=1.3, d=0.8, and n=1. The price given by model for European call is then $16.196. Now, the b) ask you tell, what kind of arbitrage possibility there is, if spotted price on market is 17 dollars, ie. the option is overpriced. Okay, this is clear as you can sell the option and create synthetic call worth 16,196 dollars. We buy 0,7 share and borrow 53,804 dollars. We make then risk free profit by 0,804 dollars. And this is the thing I don't understand. In what kind of world is this possible? I mean, if I price the call with model, where do I know if the option price is the "true" value that I can make risk free arbitrage? What is this worth, because if there is not certainty that call "true" price is 16,196 dollars how can I suppose to go in arbitrage? So am I right if i say that if market would be really EFFICIENT and all assumptions regarding the model holds, this kind of arbitrage is possible in THEORY. But because this is just mathematical formula we can never be sure if it is the theoretical value and so we cannot gain risk free arbitrage by these transactions? So the last point is, do I understand this right, or how should I interpret theoretical option value and martket value? What is the benefit after all to use these kind of pricing models? I am bit confused with the thing that books are all the time telling about risk free arbitrage and theoretical values, but in what kind of world it is possible to make this risk free profit as we cannot know the true value for sure and the fact that if the price will be the theoretical value in future. Thank you for answering, I appreciate it. ## Answer by dm63 (score 3) https://quant.stackexchange.com/a/44595 I think you have the correct understanding. The arbitrage is only possible if the risk-neutral probability distribution of the stock is perfectly known, as it is in your simple binomial model. In the real world you can never know the precise distribution, so you cannot create a true arbitrage between an option and its underlying stock in this manner. That is not to say arbitrages are impossible in the real world. For example, if market prices are such that put/call parity is violated, there is an arbitrage that can be exploited regardless of the assumed probability distribution.
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