Martingale Correction for Exponential Lévy Price Processes
Summary
The document shows how to choose a drift adjustment for an exponential Lévy asset price so that its discounted, dividend-reinvested value is a martingale under the risk-neutral measure. The key step conditions on the natural filtration: the current process value is known, while the future Lévy increment is independent of that information and has the distribution of an increment over the elapsed interval. This reduces the conditional expectation to the current price multiplied by a deterministic factor.
The Lévy characteristic exponent gives the exponential moment needed for that factor. Choosing the martingale correction to cancel the exponent at the argument corresponding to the asset price makes the conditional expectation match the risk-free growth over the interval. The answer explains why checking the unconditional expected price can suffice in this specific model: stationary, independent increments and the exponential form make the correction time independent. The reasoning assumes the relevant exponential moment exists and constant rates and dividend yield.
Key ideas
- A risk-neutral discounted asset price must satisfy the conditional expectation property of a martingale.
- Lévy process increments are independent of the past and stationary in distribution.
- The conditional expectation factors into the current price and an exponential moment of the future increment.
- A drift correction derived from the Lévy characteristic exponent enforces the martingale condition.
- The correction is time independent when the required exponential moment exists and the model has stationary independent increments.
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Full text
# Discounted price process - martingale
# Discounted price process - martingale
I have a process $S_{t}=S_{0}e^{\left(r-q\right)t+mt+X_{t}}$, where $X_t$ is a Levy process and I want to check for which $m$ the process $e^{-(r-q)t}S_t$ is a martingale. The third condition of a martingale states that for $s\leq t$ $$E(e^{-(r-q)t}S_t|F_s)=e^{-(r-q)s}S_s,$$ where $F_s$ is the filtration generated by the process $S_t$.
Many authors write that this process is a martingale when $E(e^{-(r-q)t}S_t)=S_0$ i.e. when $m=-\frac{1}{t}\ln\left(\phi_{X_{t}}\left(-i\right)\right)$, where $\phi_{X_t}$ is the characteristic function of $X_t$.
Why don't they condition on $F_s$ when they verify that the process is a martingale?
## Answer by Kevin (score 4, accepted)
https://quant.stackexchange.com/a/59365
An exponential Lévy process is typically modelled via $$ S_t = S_0\exp\left(\left(r-q+\omega\right)t+X_t\right),$$ where $X_t$ is a Lévy process with $X_0=0$. A Lévy process includes three model features: a linear drift, diffusive shocks and jumps (which may be large and rare or small and frequent). The number $\omega$ is called martingale correction or Jensen's correction and ensures the martingale property.
For our standard finance theory to work, the reinvested and discounted stock price, $S_te^{-(r-q)t}$, needs to be a martingale under $\mathbb{Q}$ (assuming constant interest rates and dividend yields). Let $(\mathcal{F}_t)$ denote the natural filtration of $X_t$. Then, for any $s\leq t$, \begin{align*} \mathbb{E}^\mathbb{Q}[S_t|\mathcal{F}_s] &= \mathbb{E}^\mathbb{Q}[S_0e^{(r-q+\omega)t+X_s+(X_t-X_s)}|\mathcal{F}_s] \\ &= S_0e^{(r-q+\omega)t} e^{X_s} \mathbb{E}^\mathbb{Q}[e^{X_t-X_s}] \\ &= S_s e^{(r-q+\omega)(t-s)} \mathbb{E}^\mathbb{Q}[e^{X_{t-s}}], \end{align*} where we used that $X_s$ is $\mathcal{F}_s$-measurable, and $X_t-X_s\overset{d}{=} X_{t-s}$ is independent of $\mathcal{F}_s$, see here.
Let $\varphi_{X_t}(u)=\mathbb{E}[e^{iuX_t}]$ be the characteristic function of the Lévy process $X_t$. The Lévy-Khintchine formula states that $\varphi_{X_t}(u)=e^{t\Psi(u)}$ which follows from the infinite divisibility of a Lévy process. The function $\Psi$ is called the characteristic exponent and captures the drift, diffusion and jump components of $X_t$.
Then, \begin{align*} \mathbb{E}^\mathbb{Q}[S_t|\mathcal{F}_s] &= S_s e^{(r-q+\omega)(t-s)} \varphi_{X_{t-s}}(-i) \\ &= S_s e^{(r-q+\omega)(t-s)} e^{(t-s)\Psi(-i)}. \end{align*} Hence, setting $\omega=-\Psi(-i)$ yields \begin{align*} \mathbb{E}^\mathbb{Q}[S_t|\mathcal{F}_s] &= S_s e^{(r-q)(t-s)}, \end{align*} which in turn implies that the discounted reinvested stock price is indeed a $\mathbb{Q}$-martingale.
Note that $$\omega=-\Psi(-i)=-\frac{1}{t}\ln\left(\varphi_{X_t}(-i)\right)$$ is independent of time. Thus, for an exponential Lévy process, the martingale property is ensured to hold if you verify that $\mathbb{E}^\mathbb{Q}[S_t]=S_0e^{(r-q)t}$.Shown in full with attribution under the source's licence. Licence: CC BY-SA 4.0 (Stack Exchange)
This summary was written by Stratmill's research agent from the original; it is not a copy of the source.