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Parallel-Shift Gamma Includes Cross Partial Derivatives

Article Quant Q&A · Author: Cettt

Summary

This discussion asks how to calculate the gamma of an interest-rate derivative when all modeled rates shift in parallel. The parallel-shift delta is the derivative of the value along the direction in which every rate moves together. Differentiating again in that same direction gives the sum of all entries of the value’s Hessian: the individual second derivatives plus the mixed partial derivatives.

The answers disagree about the interpretation. One describes the full gamma matrix and suggests that correlations or principal component analysis may help summarize rate sensitivities. Another correctly notes that a deterministic parallel shift fixes the direction of the move. Under the smoothness assumed in the question, that directional second derivative still includes cross terms; simply summing the diagonal terms omits them in general. A diagonal-only expression requires additional assumptions, such as no mixed curvature, and is not the general parallel-shift gamma. The exchange offers no product-specific numerical example or empirical comparison.

Key ideas

  • Parallel-shift delta is a directional derivative along the vector in which every rate moves together.
  • Differentiating that delta in the same direction sums every element of the Hessian, including mixed partials.
  • The sum of diagonal second derivatives alone does not generally equal parallel-shift gamma.
  • A gamma matrix describes curvature across rate coordinates, while a parallel scenario selects a particular direction through that matrix.

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Full text
# Gamma of interest rate derivatives


# Gamma of interest rate derivatives












consider an interest rate derivative whose value $V$ depends on $n$ interest rates $r_1, \dots, r_n$. Hence $V$ is a function in $n$ variables $V(r_1, \dots, r_n)$. My question concerns the gamma $\gamma$ of this derivative with respect to parallel shifts.

Does it "always" hold that $$ \gamma(r_1, \dots, r_n) = \sum_{i = 1}^n \frac{\partial^2 V}{\partial r_i^2}(r_1, \dots, r_n). $$

To clarify the notation: I define the delta $\delta$ of the derivative with respect to parallel shifts as $$ \delta(r_1, \dots, r_n) = \lim_{h \rightarrow 0} \frac{V(r_1 + h, \dots, r_n + h) - V(r_1, \dots, r_n)}{h}, $$ and $\gamma$ is then defined as $$ \gamma(r_1, \dots, r_n) = \lim_{h \rightarrow 0} \frac{\delta(r_1 + h, \dots, r_n + h) - \delta(r_1, \dots, r_n)}{h}. $$

From a mathematical standpoint, I think the identity should not hold in general since mixed partial derivatives (i.e. $\frac{\partial^2 V}{\partial r_i r_j}$) should be considered as well. I also assume that $V$ is sufficiently smooth function such that all second partial derivatives exist and are continuous. However, literature seems to suggest that the identity holds in general. What do you guys think?

## Answer by user35980 (score 2)

https://quant.stackexchange.com/a/60724

It's my understanding that indeed the cross partial derivative terms do have a contribution - so you're correct to say that what u really have to work with is a gamma matrix $$\gamma=[\frac{d^2V}{dr_idr_j}]_{i,j}.$$ In essence, the cross partial terms $\frac{d^2}{dr_idr_j}$ allude to the correlation between the various rates $(r_1,...,r_n)$. Assuming a high (c. 90%) correlation these terms generally can be ignored. For this reason the gamma as computed by your stated formula is a kind of 'local' gamma as opposed to a 'global' gamma given by the entire matrix. For calculating this 'global' gamma, banks generally use some form of principal components analysis (or some other linear transformation) as it's a less computationally expensive way of capturing the majority of the variance in rate sensitivity without having to compute the whole matrix.

## Answer by John (score 0)

https://quant.stackexchange.com/a/68666

Correct. You're starting with specifying the scenario where all rates move parallel. The correlation implicit there is 100%. There is nothing stochastic left. The gamma to a parallel shift is as cited originally. No matrix is needed.

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