Stochastic Interest Rates, Filtrations, and Risk-Neutral Measures
Summary
The document asks whether interest rates in binomial and continuous-time pricing models can be stochastic while still allowing a change to a risk-neutral measure. Its two-period example treats the rate as an additional random outcome that is not determined by the stock-price history. That creates more terminal states than the proposed stock and money-market hedge can cover, so the example appears incomplete for replication.
The response distinguishes the bank-account risk-neutral measure, which relies on an adapted bank-account process, from a bond-based measure such as the T-forward measure. Under the latter, a zero-coupon bond serves as numeraire, and its return can be stochastic before maturity. The short exchange offers a conceptual distinction rather than a full proof: it does not specify all model assumptions or establish general conditions for arbitrage-free pricing or hedging.
Key ideas
- A stochastic rate that is not observable from the stock filtration can add states that a stock-and-cash hedge cannot distinguish.
- In the example, the extra rate outcomes create more terminal cases than the listed hedge positions can match.
- The usual bank-account risk-neutral measure is associated with an adapted bank-account process.
- A bond maturing at the pricing horizon can instead serve as numeraire for a forward measure.
- The exchange sketches this distinction but does not give a general theorem or detailed model conditions.
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Full text
# stochastic interest rate in binomial pricing model and in continuous models
# stochastic interest rate in binomial pricing model and in continuous models
Is the interest rate allowed to be truly stochastic in the binomial pricing model and in continuous models so that we are still able to switch to the risk-neutral measure?
Shreve mentions multiple times that the interest rate has to be adapted to the stock price process's filtration. My understanding is as follows: let a binomial pricing model of two periods be given. Let us index prices with $i$: $S_i$ for the stock price in $i^{th}$ period. Also let us index prices with $u$ and $d$ for when the previous move in the price was up or down. In other words, $S_{1}^{u}$ stands for the stock price in the first period, whereby it has just moved up ($S_0*u$). Also let the interest rate be fully random and not adapted to the filtration of the discrete stock price process. Index the interest rates similarly but let $r^A$ stand for outcome $A$ and $r^B$ stand for outcome $B$. In other words, $r$ is a discrete R.V. and has two possible outcomes. As always, suppose $d \leq (1+r) \leq u$ to prevent arbitrage. To hedge a short position in that option, we have to hedge eight states of nature:
- $r_1^A, S_2^{uu}$
- $r_1^A, S_2^{ud}$
- $r_1^B, S_2^{uu}$
- $r_1^B, S_2^{ud}$
- $r_1^A, S_2^{du}$
- $r_1^A, S_2^{dd}$
- $r_1^B, S_2^{du}$
- $r_1^B, S_2^{dd}$
Also, because we can readjust hedge only based on the information (filtration) available to us at time $t$, let us denote $M$ as the initial investment into the money market account and let $\delta_i(S_i^{w}, r_i^{w})$ be the hedging position in stocks at time $i$, depending on the outcomes $w$. Say, $\delta_1(S_1^u, r_1^A)$ would the position in stocks that we take in period 1 when the stock has moved up and the interest rate has ended up $A$. Then there are six such hedging positions based on filtration possible:
- $\delta_0$
- $M$
- $\delta_1(S_1^u, r_1^A)$
- $\delta_1(S_1^d, r_1^A)$
- $\delta_1(S_1^u, r_1^B)$
- $\delta_1(S_1^d, r_1^B)$
Eight equations in six unknowns - unhedgeable. We need one more leverage factor to hedge this. Is this correct?
A colleague quant has told me that the interest rate process does not have to adapted to the filtration of the stock process and that it's only a technical assumption. Well yes but then we cannot switch to the risk-neutral measure because we cannot hedge, and the risk-neutral measure is all about hedging... Is this the correct understanding of mine?
## Answer by Magic is in the chain (score 1)
https://quant.stackexchange.com/a/46828
I think both are right in different ways! Risk neutral measure is the measure associated with the bank account, and the standard definition of bank account is indeed an adapted process. And technical conditions are indeed there for a reason.
But then you can have, say the T-measure, which uses zero coupon, whose return is stochastic in each step, except in the last step from $T-1$ to $T$, because the payoff at T is known. And the bank account return is nothing but the return of the bond that matures at next time step.Shown in full with attribution under the source's licence. Licence: CC BY-SA 4.0 (Stack Exchange)
This summary was written by Stratmill's research agent from the original; it is not a copy of the source.