Using Itô's Lemma for Log Prices and Quadratic Covariation
Summary
The answer derives the log-price identity for a diffusion with drift and volatility by applying Itô's lemma to the logarithm. The second derivative contributes a correction involving integrated squared volatility, yielding the relationship between the change in log price, the stochastic integral of inverse price against price changes, and realized quadratic variation in continuous time.
It also addresses a product-process example. It explains that an Itô process is a continuous semimartingale, while a finite-variation process has zero quadratic variation and zero quadratic covariation with a continuous semimartingale. The example still requires showing that its deterministic factor has bounded variation; the response identifies this requirement but does not work through that proof in detail. These statements rely on standard stochastic-calculus results and the stated process assumptions.
Key ideas
- Applying Itô's lemma to the logarithm introduces a correction proportional to integrated squared volatility.
- The log-price change can be written using the inverse-price stochastic integral and a volatility correction.
- An Itô process is a continuous semimartingale with martingale and finite-variation components.
- A finite-variation process has zero quadratic variation and zero covariation with a continuous semimartingale.
- The product example requires verifying that its deterministic factor has bounded variation.
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# Clarification of Ito's lemma
# Clarification of Ito's lemma
I was looking at the various examples provided in the discussion Worked examples of applying Ito's lemma
One such example is 9.1 (c). This states that -
if $S_t =\! S_0 + \int\limits_{0}^{t} \mu_u S_u du + \int\limits_{0}^{t} \sigma_u S_u dW_u$ with $\mu=\left(\mu_t \right)_{t\geq0}, \sigma=\left(\sigma_t \right)_{t\geq0}, \int\limits_{0}^{T} |\mu_s| + |\sigma_s|^2 ds < \infty$. Then $\int\limits_{0}^{T} \sigma^2_s ds = -2\log \frac{S_T}{S_0} + \int\limits_{0}^{T} \frac{2}{S_u} dS_u$
Then it says $\frac{S_T}{S_0} = e^{\int\limits_{0}^{T} \sigma_s dW_s - \int\limits_{0}^{T} \left(0.5\sigma_s^2 - \mu_s \right) ds}$, which I understand the derivation.
I then failed to grasp the remaining part which shows that : $\log S_T - \log S_0 = \int\limits_{0}^{T} \frac{1}{S_u} dS_u -0.5 \int\limits_{0}^{T} \sigma_u^2 du$
2nd example goes for 4. This states that -
if $X_t =\! e^{W_t+0.5t} + e^{W_t-0.5t}$, then $dX_t =\! X_t dW_t + e^{W_t+0.5t}dt$.
To prove this, it is taken that $X_t=Z_tY_t, Z_t = e^{W_t-0.5t}, Y_t = e^t + 1$. It sates that the process $Z_t$ is continuous semi-martingale and $Y_t$ is continuous semi-martingale of bounded variation. Therefore it holds that $\left[ ZY \right]=0$. My questions are
- Why $Z$ is continuous semi-martingale and $Y$ is continuous semi-martingale with bounded variation? What is required to prove them so?
- How to show exactly that $\left[ZY\right] = 0$
Your pointer will be highly helpful
## Answer by ir7 (score 4)
https://quant.stackexchange.com/a/55918
For the first one, we have:
$$ dS_t = \mu_t S_t dt + \sigma_tS_t dW_t $$ and note that
$$ (dS_t)^2 = \sigma_t ^2 S_t^{2} dt. $$
We apply Ito formula to
$$ f(S_t) = \ln S_t. $$
As $f'(x) = x^{-1}$ and $f^{''}(x)= -x^{-2}$, we get:
$$ d \ln S_t = S_t^{-1} dS_t - 0.5 S_t^{-2} (dS_t)^2 $$
which is equivalent to
$$ d \ln S_t = S_t^{-1} dS_t - 0.5 \sigma_t^2 dt. $$
Integration from $0$ to $T$ gives:
$$ \ln S_T - \ln S_0 = \int_0^T S_t^{-1} dS_t - 0.5 \int_0^T \sigma_t^2 dt. $$
For the second one:
A process has bounded variation if almost all its paths are functions with bounded variation.
This needs to be proven for $Y_t$.
For the rest of the questions, you can take as facts (proven in many books on stochastic calculus) that:
- Ito processes are continuous semimartingales (with the two pieces, continuous local martingale and continuous finite variation process, visible).
- Finite variation processes (bounded variation on every finite time interval, with probability $1$) have $0$ quadratic variation.
- The quadratic covariation between a finite variation process and a continuous semimartingale is $0$.Shown in full with attribution under the source's licence. Licence: CC BY-SA 4.0 (Stack Exchange)
This summary was written by Stratmill's research agent from the original; it is not a copy of the source.