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Why a Vanilla Call’s Vega Peaks Near the Money

Article Quant Q&A · Author: Axel Haddar

Summary

The document raises a question about a statement in a paper on variance swaps: a stock call option’s vega is greatest when the option is at the money. The author wonders whether this is because vanilla options are nearly linear in volatility at that point, but provides no derivation or answer.

It therefore identifies a useful options concept without establishing why the vega peak occurs or how that observation relates to variance swaps. The note is an incomplete question rather than a worked explanation, and it gives no calculations, evidence, or caveats beyond its limited framing. Readers would need additional material to understand how option moneyness affects vega or how a variance swap’s exposure differs from a single option’s vega.

Key ideas

  • The note asks why a stock call option’s vega is largest at the money.
  • The author suggests near-linearity in volatility as a possible explanation but does not develop it.
  • The document contains no answer, calculation, or evidence connecting the question to variance swaps.

Tags

Full text
# Variance Swap Vega


# Variance Swap Vega












I am currently reading the paper of Derman and al for my master thesis on Variance Swap. At one point one says that "The variance vega is largest when the option is ATM", considering here a call option on a stock.

I must say, I am having some difficulties to understand that. The only reason I came up with is that vanilla option are almost linear in volatility at ATM.

Edit:

In order to clarify my questions which is not clearly explicit.

Shown in full with attribution under the source's licence. Licence: CC BY-SA 4.0 (Stack Exchange)

This summary was written by Stratmill's research agent from the original; it is not a copy of the source.