Why American Calls Equal European Calls Without Dividends
Summary
The document explains why early exercise does not add value to an American call when there are no dividends or repo costs and interest rates are nonnegative. Put-call parity implies that a European call is worth at least its intrinsic value under these assumptions. Exercising early would realize only intrinsic value, while holding the option preserves time value, so the early-exercise right has no economic benefit and the American and European calls have the same value.
A second explanation compares exercising with selling the underlying short and later closing that position using either the option or the market. The equality is conditional, not universal: dividends, repo costs, or rates and forwards that violate the stated discounted-forward condition can change the conclusion. The document presents a theoretical argument rather than empirical evidence.
Key ideas
- Without dividends or repo costs and with nonnegative rates, put-call parity bounds a European call at or above intrinsic value.
- Early exercise of the American call then offers no advantage over retaining the option.
- Under the stated assumptions, American and European call values are equal.
- The result may fail when dividends, repo costs, or the discounted-forward condition differ.
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Full text
# What is the economic reason for the equality in value of an American call and European call?
# What is the economic reason for the equality in value of an American call and European call?
In a previous question this question came up.
In my mind, if I'm holding an option at time t, then there are possible future price paths where at t+k the option will be ITM but at T the option will be out of the money. Thus, I'd expect the value of an American call at time t to be higher than the European call. Apperently this is not the case, I found this reference that explains it in math, but LocalVolatility says there is a simple economic reason that I am missing. What is it ?
## Answer by LocalVolatility (score 6)
https://quant.stackexchange.com/a/43736
In your question you consider a model with no dividends or repo rates. Put-call parity in this setting is
$$ C_0 - P_0 = S_0 - K e^{-r T} $$
Which implies that
$$ C_0 \geq \max \left\{ S_0 - K e^{-r T}, 0 \right\} $$
since $P_0 \geq 0$. When $r \geq 0$, then
$$ S_0 - K e^{-r T} \geq S_0 - K $$
where the right-hand side is the intrinsic value. Thus, the value of a European call option is always at least as high as the intrinsic value. Exercising the American option would only pay the intrinsic value. Thus, there is no advantage in exercising early. The corresponding right is worthless and the American call price is the same as the European call price.
Note that this result assumes that there are no dividends or repo rates and interest rates are non-negative. In the more general case it only holds when the discounted forward is not smaller than the spot. i.e. $F_t(T) e^{-r (T -t)} \geq S_t$.
## Answer by Prabhnoor Duggal (score 3)
https://quant.stackexchange.com/a/43879
Although it might seem that due to its flexibility, the American call option must be worth more than the European call, now we will look at why the call option is never optimal to exercise before expiry and hence why they both have the same value.
Suppose instead of exercising the American call option at time T1( which would give you a payoff of S-K), you sell the stocks short at T1( +S(T1) ) and buy them back at expiry by either exercising your option (price: K) or at the market price S whichever is lower. Hence they have the same value.
To summarize,
If you exercise the American call option at t1, profit = S(t1) - K
### Second choice:
but now, you short your stocks at t1 : +S(t1) and at maturity, you decide to close the short either by exercising your contract(-K) or by buying the stocks in market (S(T)) whichever is lower.Shown in full with attribution under the source's licence. Licence: CC BY-SA 4.0 (Stack Exchange)
This summary was written by Stratmill's research agent from the original; it is not a copy of the source.