Why American Option Vega and Gamma Diverge Near Early Exercise
Summary
The document explains why the European Black–Scholes relationship between vega and gamma generally does not carry over to American options. Early exercise creates a boundary that changes the option’s value and sensitivities. For a put with a positive interest rate, sufficiently low spot can make immediate exercise optimal; beyond that boundary, the option behaves like a short stock position, with delta at negative one and gamma at zero. Gamma can jump near the boundary, while vega need not share that discontinuity.
Far from the exercise boundary, early exercise is unlikely and the option behaves more like a European contract, so the familiar vega–gamma relation may be a useful approximation. A second explanation decomposes American value into a European component and an early-exercise premium, then attributes deviations to the premium’s own sensitivities. The discussion gives a model-based example and a qualitative boundary argument, but no general approximation error bound; the relationship depends on contract and market conditions.
Key ideas
- Early exercise changes American option prices and Greeks relative to European options.
- For an American put with positive rates, optimal exercise at low spot can leave the option with delta of negative one and zero gamma.
- Gamma may change abruptly near the exercise boundary, whereas vega need not do so.
- The European vega–gamma relation can be an approximation when the exercise premium and its sensitivities are small.
- The decomposition into European value and early-exercise premium explains where deviations arise.
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Full text
# American Options relation between greeks
# American Options relation between greeks
Considering an American option in a Black-Scholes model, is there a relation between Vega and Gamma as it holds in the European case?
I am aware an exact relation would be difficult to find. But in practice is there a kind of approximate relation between these two quantities?
## Answer by Chris Taylor (score 21, accepted)
https://quant.stackexchange.com/a/35166
No, you should not expect such a relationship to hold in general. The reason is that American options have an "exercise barrier" which European options don't, and this results in different prices and greeks.
In the case of put options (with interest rate $r>0$) as the spot price falls, at some point it becomes optimal to exercise early and take the cash. Beyond this point, the option behaves like a short position in the stock, so its delta is exactly -1 and its gamma is zero. As the spot crosses through this barrier, the gamma jumps.
Vega, on the other hand, does not have such a discontinuity. The chart below shows the price of a European and American put with strike 100, three months to maturity, risk-free rate 15% and volatility 20%. The European prices and greeks are from the Black-Scholes model, and the American prices and greeks are from a binomial tree.
Note that when the spot price is sufficiently far from the early exercise barrier, it is unlikely to cross it, and the option behaves like a European. In this case you expect the standard relationship between gamma and vega,
$$\nu = \sigma\tau S^2 \Gamma$$
will approximately hold. The plot below shows how this relationship holds when the spot price is sufficiently far above the strike, but breaks down when it approaches the early exercise barrier.
## Answer by Brian B (score 3)
https://quant.stackexchange.com/a/35165
One way to think of American-exercise options is to break their value $V_A$ down into a value due to the european exercise, $V_E$, and a "premium" due to the possibility of early exercise, $V_P$
$$ V_A = V_E + V_P $$
Since the differentiation operator is linear, we then have similar terms for gamma and vega
$$ \Gamma_A = \Gamma_E + \Gamma_P $$
$$ \aleph_A = \aleph_E + \aleph_P $$
For the "european component" the standard relation holds
$$ \aleph_E = S^2 \sigma \tau \Gamma_E $$
To the extent that the exercise premium $V_P$ and its derivatives are small compared to $V_E$ and its derivatives, the standard european option relationship holds in approximation
$$ \begin{aligned} \aleph_A &= S^2 \sigma \tau \Gamma_E + \aleph_P \\ &= S^2 \sigma \tau (\Gamma_A-\Gamma_P) + \aleph_P \\ &= S^2 \sigma \tau \Gamma_A + \underbrace{(\aleph_P -S^2 \sigma \tau\Gamma_P)}_{\text{Small terms}} \end{aligned} $$ and similarly
$$ \Gamma_A = \frac{\aleph_A}{S^2 \sigma \tau} + \underbrace{\Gamma_P - \frac{\aleph_P}{S^2 \sigma \tau}}_{\text{Small terms}} $$Shown in full with attribution under the source's licence. Licence: CC BY-SA 4.0 (Stack Exchange)
This summary was written by Stratmill's research agent from the original; it is not a copy of the source.