Why Factor-Neutral Variance Maximization Is Unbounded
Summary
The document examines a portfolio problem that seeks to maximize variance while requiring zero exposure to each listed risk factor. It explains why those constraints alone do not produce a finite maximum: if a feasible portfolio exists, scaling all its weights by a factor greater than one preserves zero factor exposure while increasing variance quadratically.
The argument shows that the optimization problem is unbounded, so reframing the variance objective as a lower-bound constraint does not supply the missing limit on portfolio size. A practical formulation would need additional constraints, such as a normalization or exposure limit, but the document does not develop a revised model or discuss which constraints are suitable. Its conclusion relies on the stated homogeneous factor constraints and the usual nonnegative covariance-based variance; it does not address other portfolio restrictions or optimization methods.
Key ideas
- Zero factor-exposure constraints remain satisfied when portfolio weights are scaled.
- Scaling feasible weights upward increases portfolio variance quadratically.
- The stated maximization problem has no finite optimum without constraints on portfolio scale.
- Turning the objective into a variance threshold does not by itself bound the portfolio weights.
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# Portfolio optimization - maximize variance with exposure to risk factors equal to zero # Portfolio optimization - maximize variance with exposure to risk factors equal to zero Optimize a portfolio such that the exposure to risk factors is zero and the variance is maximized (instead of traditional minimization problem). so the optimization problem look like: $$maximize\;w^T\,\Sigma\,w$$ With following constraints: $$\beta_0\,w=0$$ $$\beta_1\,w=0$$ $$\beta_2\,w=0$$ $$\beta_3\,w=0$$ Where $$\Sigma - covariance\,matrix$$ $$\beta_0..._3 - factor\,exposure$$ I am told that this is a non-convex problem. Can I convert this into an SDP with some relaxations? I could convert the objective function into a quadratic constraint such as below: $$w^T\,\Sigma\,w > Min$$ Please advise. ## Answer by Chris Taylor (score 1, accepted) https://quant.stackexchange.com/a/25416 There is no solution. If $w$ is a solution to the original problem, then consider $aw$ with $a>1$ $$\beta_i(aw) = a(\beta_i w) = 0$$ and $$(aw)^T\Sigma(aw) = a^2 (w^T\Sigma w) > w^T\Sigma w$$ so the original solution $w$ was not a maximum.
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